physics help please thanks?
Mar-12-2010 Posted under Ski Squaw
Squaw Valley ski area in California claims that its lifts can move 46400 people per hour. If the average lift carries people about 200 m (vertically) higher, estimate the maximum total power needed. (Assume an average mass per person of 70 kg.)
The energy to move vertically 200 m one 70 kg person is mgh = 70Kg*10m/sec^2*200m = 140000 Joules.
The minimum power to move vertically 200 m 464000 people is
=140000 Joules * 46400/sec (answer is in Watts)
Note this is the minimum power assuming 100 % efficiency. In reality, you almost never achieve 100 % efficiency. Hence, the maximum power is impossible to calculate without an assumed efficiency.
Ron
The energy to move vertically 200 m one 70 kg person is mgh = 70Kg*10m/sec^2*200m = 140000 Joules.
The minimum power to move vertically 200 m 464000 people is
=140000 Joules * 46400/sec (answer is in Watts)
Note this is the minimum power assuming 100 % efficiency. In reality, you almost never achieve 100 % efficiency. Hence, the maximum power is impossible to calculate without an assumed efficiency.
Ron
References :
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